find three sets of values for x and y to make x mi/y min= 4 mi/ 32 a proportion.
To find three sets of values for x and y that make the given expression a proportion, you need to solve for x and y using the given ratio and equation.
The given equation is:
x mi / y min = 4 mi / 32
Let's cross-multiply to solve for x and y:
x * 32 = y * 4
Now, rearrange the equation to solve for y:
y = (x * 32) / 4
To find three sets of values, you can assign different values to x and calculate the corresponding values of y.
Set 1:
Let's say x = 2
y = (2 * 32) / 4
y = 64 / 4
y = 16
So, the first set of values is x = 2 and y = 16.
Set 2:
Let's say x = 6
y = (6 * 32) / 4
y = 192 / 4
y = 48
So, the second set of values is x = 6 and y = 48.
Set 3:
Let's say x = 10
y = (10 * 32) / 4
y = 320 / 4
y = 80
So, the third set of values is x = 10 and y = 80.
Therefore, three sets of values that make the equation x mi / y min = 4 mi / 32 a proportion are:
1. x = 2, y = 16
2. x = 6, y = 48
3. x = 10, y = 80