find three sets of values for x and y to make x mi/y min= 4 mi/ 32 a proportion.
To find the three sets of values for x and y that make the equation x mi / y min = 4 mi / 32 true, we need to make sure that the ratio on the left side (x/y) is equal to the ratio on the right side (4/32).
To solve this equation, we can cross-multiply to find an equivalent equation. So, we have:
x mi * 32 = 4 mi * y min
By simplifying this equation, we get:
32x mi = 4y min
Now, we can rearrange this equation to solve for y min:
y min = (32x mi) / 4
Let's find three different sets of values for x mi and y min:
1. Let x mi = 2
Substituting this value into the equation, we get:
y min = (32 * 2) / 4 = 64 / 4 = 16
So, one set of values is x mi = 2 and y min = 16.
2. Let x mi = 6
Substituting this value into the equation, we get:
y min = (32 * 6) / 4 = 192 / 4 = 48
So, another set of values is x mi = 6 and y min = 48.
3. Let x mi = 10
Substituting this value into the equation, we get:
y min = (32 * 10) / 4 = 320 / 4 = 80
So, a third set of values is x mi = 10 and y min = 80.
Therefore, three sets of values for x and y to make the proportion x mi / y min = 4 mi / 32 true are:
1. x mi = 2, y min = 16,
2. x mi = 6, y min = 48,
3. x mi = 10, y min = 80.