# Physics

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A test charge of +3.00 10-6 C experiences a downward electrostatic force of 11 N when placed at a certain point in space. What are the magnitude and direction of the electric field at this point?

• Physics -

The field direction is down and the field strength is 11/3*10^-6 = 3.7*10^6 N/C (or volts/meter)

This is close to the field strength that casues air breakdoown.

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