posted by Lindt .
What is the mass of iron (g) produced from 227.4 of iron(III) oxide ?
227.4g Fe2O3 x (2*atomic mass Fe/molar mass F2O3) = ?
__Fe2O3(l) + __CO(g)----1500 degrees Celsius--->__Fe(l) + CO2(g)
Fe2O3(l) + 3CO(g) heat ==>2Fe(l) + 3CO2(g)
mols Fe2O3 = grams/molar mass
Convert mols Fe2O3 to mols Fe using the coefficients in the balanced equation.
Convert mols Fe to g. g = mols x molar mass
You will obtain the same answer as my short answer above.