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What is the mass of iron (g) produced from 227.4 of iron(III) oxide ?

  • Chemistry -

    227.4g Fe2O3 x (2*atomic mass Fe/molar mass F2O3) = ?

  • Chemistry -

    __Fe2O3(l) + __CO(g)----1500 degrees Celsius--->__Fe(l) + CO2(g)

  • Chemistry -

    Fe2O3(l) + 3CO(g) heat ==>2Fe(l) + 3CO2(g)

    mols Fe2O3 = grams/molar mass
    Convert mols Fe2O3 to mols Fe using the coefficients in the balanced equation.
    Convert mols Fe to g. g = mols x molar mass

    You will obtain the same answer as my short answer above.

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