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trig

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How do I find the exact value of sin (pi/24)?

  • trig -

    sin π/6 = 1/2
    cos π/6 = √3/2

    sin(x/2) = √(1-cosx) / 2
    cos(x/2) = √(1+cosx) / 2

    apply the half-angle formula twice to get

    sin π/24 = 1/2 √(2-√(2+√3))

  • trig -

    I am not under standing could you show me ? to tell me ?

  • trig -

    I applied the half angle formula for sin and I got the square root of 2 minus the square root of 3 divided by 2 . and for cos I got thesqurof 2 plus thesqr of3divided by 2 .

  • trig -

    I really need help . I find this hard Steve .

  • trig -

    Do I subtract ?

  • trig -

    sin π/6 = 1/2
    cos π/6 = √3/2
    so,
    cos π/12 = √(1+√3/2) / 2

    sin π/24 = √(1-cos π/12) / 2
    = 1/2 √(1 - (√(1+√3/2) / 2))
    = 1/2√2 √(2 - √(1+√3/2))
    = 1/4 √(2√2 - √(1+√3))
    ...

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