Chemistry AP

posted by .

It was determined that a 0.10 M solution of an acid was only 2.5% ionkzed. Find the Ka and pKa for the acid.

  • Chemistry AP -

    HA + H2O---> H3O+ + A-

    Ka=[H3O+][A-]/[HA]


    ..........HA I H3O+ I A-

    I.........I 0.1 M I 0 I 0 I
    C........I-2(0.1*0.025) I (0.1*0.025)I (0.1*0.025) I
    E.........I 0.1-2(0.1*0.025) I (0.1*0.025) I (0.1*0.025)


    Ka=[(0.1*0.025][(0.1*0.025]/[0.1-2(0.1*0.025]


    pka=-log(ka)

  • Chemistry AP -

    Opps,


    HA + H2O---> H3O+ + A-

    Ka=[H3O+][A-]/[HA]


    ..........HA I H3O+ I A-

    I.........I 0.1 M I 0 I 0 I
    C........I-2(0.1*0.025) I (0.1*0.025)I (0.1*0.025) I
    E.........I 0.1-(0.1*0.025) I (0.1*0.025) I (0.1*0.025)


    Ka=[(0.1*0.025][(0.1*0.025]/[0.1-(0.1*0.025]


    pka=-log(ka)

    I apologize about that one.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    Part A: Unknown Acid use 1gram and mix with 120 mL of distilled water Determine the concentration of the acid by titrating with 0.0998 M of NaOH Concentration of NaOH= 0.0998M Volume of NaOH= 3.5 mL # moles of NaOH= Initial Concentration …
  2. Organic chemistry

    the pka of benzoic acid is 4.2. show mathematically that this acid is 50% ionized. Use results of part a t oexplain why precipitation is incomplete if the pH of an aquesous solution of benzoate ion is lowered only to ph 7 by adding …
  3. chemistry

    when 1.00 g of stearic acid ( a saturated fatty acid) is dissolved in water, then diluted to exctly 10.00 ml, the PH of the resulting solution is 2.73.the fornula weight of steric acid is 284.5. calculate ka and pka for this acid
  4. chemistry

    Run # Volume NaOH used (mL) 1 4.1 2 4.3 3 2.8 Concentraion of NaOH: 0.113 M pH of acid: 2.84 the questions are: #moles of NaOH: ?
  5. chemistry buffers

    What molar ratio of HPO4 2- to H2PO4 - in solution would produce a pH of 7.0?
  6. Chemistry

    Determine the pH of the following solutions: a) A 250.0 mL solution that contains 0.125 M benzoic acid and 0.147 M sodium benzoate. b) The solution in part (a) after 30.0 mL of 0.510 M hydrochloric acid has been added. a. Ka = 6.3 …
  7. chemistry

    Arrange the acids I) hydrogen selenate ion (HSeO− 4 ), pKa = 1.92; II) phosphorous acid (H3PO3), pKa1 = 2.00; III) phosphoric acid (H3PO4), pKa = 2.12; IV) selenous acid (H2SeO3), pKa = 2.46; in increasing order of strengths. …
  8. chemistry

    Arrange the acids I) hydrogen selenate ion (HSeO− 4 ), pKa = 1.92; II) phosphoric acid (H3PO4), pKa = 2.12; III) selenous acid (H2SeO3), pKa = 2.46; IV) phosphorous acid (H3PO3), pKa1 = 2.00; in increasing order of strengths. …
  9. chemistry- titration

    Once you have calculated your Ka value, use the data to find the concentration of the unknown acids. Vol. of acid solution=25mL concentration of NaOH used = 1M Buffer (pH) = 8.35 at 11.5mL 1/2 11.5=5.75mL which is a pH of 3.58 I did …
  10. Chemistry

    A solution is prepared by dissolving 0.1 mol of ethanoic acid (CH3COOH) in 500ml of water at 25 C. pKa of ethanoic acid is 4.7. What is the pH of the solution?

More Similar Questions