The bearing of Q from P is 060¤ while the bearing of R from Q is 150¤ if PQ=QR find the bearing of R from P
I made a sketch , and it is easy to see that in triangle
PQR, angle Q = 90° and angle QPR = 45°
then the bearing from R to P = 285°
O67 in degree
To find the bearing of R from P, we need to add the bearings of P from Q and Q from R.
Given:
Bearing of Q from P = 060°
Bearing of R from Q = 150°
Step 1: Find the bearing of P from R.
Since we know the bearing of Q from P and Q from R, we can subtract the bearing of Q from P from 180° to find the bearing of P from R.
Bearing of P from R = 180° - Bearing of Q from P
Bearing of P from R = 180° - 060°
Bearing of P from R = 120°
Step 2: Find the bearing of R from P.
To find the bearing of R from P, we need to subtract the bearing of P from R from 180°.
Bearing of R from P = 180° - Bearing of P from R
Bearing of R from P = 180° - 120°
Bearing of R from P = 60°
Therefore, the bearing of R from P is 60°.
To find the bearing of R from P, we can add the bearings of P from Q and the bearing of R from Q since we have the bearings of PQ and QR.
Given:
Bearing of Q from P = 060°
Bearing of R from Q = 150°
Step 1: Add the bearings
Bearing of R from P = Bearing of P from Q + Bearing of R from Q
Step 2: Substitute the given values
Bearing of R from P = 060° + 150°
Step 3: Perform the addition
Bearing of R from P = 210°
Therefore, the bearing of R from P is 210°.