The engine on a 0.2kg model airplane exerts a forward force on the plane of 10N. If the plane accelerates at 2m/s2, what is the magnitude of the resistive force due to the wind acting on the airplane?
Let the resistive force = f
F=ma
10-f=0.2x2
f=9.6N
To find the magnitude of the resistive force due to the wind acting on the airplane, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
Given:
Mass of the model airplane (m) = 0.2 kg
Force exerted by the engine (F) = 10 N
Acceleration of the airplane (a) = 2 m/s^2
We can rearrange the equation F = ma to solve for the resistive force (R):
R = F - ma
Substituting the given values into the equation:
R = 10 N - (0.2 kg)(2 m/s^2)
Calculating the result:
R = 10 N - 0.4 N
Therefore, the magnitude of the resistive force due to the wind acting on the airplane is 9.6 N.
To find the magnitude of the resistive force due to the wind acting on the airplane, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
The net force acting on the airplane can be calculated as the difference between the forward force exerted by the engine and the resistive force due to the wind.
Given:
Mass of the airplane (m) = 0.2 kg
Forward force exerted by the engine (F) = 10 N
Acceleration of the airplane (a) = 2 m/s^2
Using Newton's second law:
Net Force (F_net) = m * a
Substituting the given values:
F_net = 0.2 kg * 2 m/s^2
F_net = 0.4 N
Now, since the net force is equal to the difference between the forward force and the resistive force, we can write:
F_net = Forward force - Resistive force
0.4 N = 10 N - Resistive force
Rearranging the equation to solve for the resistive force:
Resistive force = 10 N - 0.4 N
Resistive force = 9.6 N.
Therefore, the magnitude of the resistive force due to the wind acting on the airplane is 9.6 N.