# algebra

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a farmer has both cickens and cattle.These animals have a total of 40 heads and 140 feet.How many chicken and how many cattle has this farmer

• algebra -

number of chickens --- x
number of cattle ---- y
x+y = 40
2x + 4y = 140 or x+2y = 70

subtract them
y = 30
then x = 10

The farmer has 10 chickens and 30 cattle

check:
20 chicken feet + 120 cattle feet = 140 feet

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