algebra

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a farmer has both cickens and cattle.These animals have a total of 40 heads and 140 feet.How many chicken and how many cattle has this farmer

  • algebra -

    number of chickens --- x
    number of cattle ---- y
    x+y = 40
    2x + 4y = 140 or x+2y = 70

    subtract them
    y = 30
    then x = 10

    The farmer has 10 chickens and 30 cattle

    check:
    10+30 = 40 heads
    20 chicken feet + 120 cattle feet = 140 feet

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