Math computations
posted by Ronni .
An examination is normally distributed with a mean score of 77 and a deviation of 6. find the percent of individuals scoring as indicated below:
between 7183
between 8365
above 89
less than 65
between 77 and 65

Z = (scoremean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z scores.