algebra 2
posted by Mikayla .
3n/(n2 7n + 10)  2n/(n28n+15)

First factor the denominators.
3n/(n^2 7n + 10)  2n/(n^28n+15)
= 3n/[(n5)(n2)] 2n/[(n5)(n3)]
= [n/(n5)] *{[3/(n2)][2/(n3)]}
= [n/(n5)] *{[3(n3)2(n2)/(n2)(n3)]}
= [n/(n5)]*(n+5)/[(n2)(n3)]
This does not seem to be getting any simpler.
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