In a measurment 0.1M Kmno4 is used.determine the volume of solution required to react with 0.158M Na2s2o3 required?

I'm sorry but you need to rework this problem. I don't understand the question.

To determine the volume of the solution required for the reaction, we can use the concept of molarity and the balanced chemical equation of the reaction.

The balanced chemical equation for the reaction between KMnO4 (Potassium permanganate) and Na2S2O3 (Sodium thiosulfate) is:

2 KMnO4 + 10 Na2S2O3 + 8 H2O → 2 MnSO4 + 10 Na2SO4 + 5 S + 8 H2SO4

From the balanced equation, we know that 2 moles of KMnO4 react with 10 moles of Na2S2O3.

Given:
Molarity of KMnO4: 0.1 M
Molarity of Na2S2O3: 0.158 M

To find the volume of KMnO4 solution needed to react with a given volume of Na2S2O3 solution, you need to use the equation:

(Moles of KMnO4) x (Volume of KMnO4 solution) = (Moles of Na2S2O3) x (Volume of Na2S2O3 solution)

Rearranging the equation, we can solve for the volume of KMnO4 solution:

Volume of KMnO4 solution = (Moles of Na2S2O3) x (Volume of Na2S2O3 solution) / (Moles of KMnO4)

Now we can plug in the known values:

(Moles of Na2S2O3) = (Molarity of Na2S2O3) x (Volume of Na2S2O3 solution) = 0.158 M x (volume of Na2S2O3 solution)

(Moles of KMnO4) = (Molarity of KMnO4) x (Volume of KMnO4 solution) = 0.1 M x (volume of KMnO4 solution)

Since 2 moles of KMnO4 react with 10 moles of Na2S2O3, the ratio is 1:5. Therefore:

(Moles of Na2S2O3) / (Moles of KMnO4) = 5

Now we can rewrite the equation for the volume of KMnO4 solution as:

Volume of KMnO4 solution = (Moles of Na2S2O3) x (Volume of Na2S2O3 solution) / (Moles of KMnO4)
= [0.158 M x (volume of Na2S2O3 solution)] / [0.1 M x (5)]

Simplifying the equation:

Volume of KMnO4 solution = 0.158 M x (volume of Na2S2O3 solution) / 0.5

Therefore, to calculate the volume of KMnO4 solution required, we need to know the volume of the Na2S2O3 solution.