Describe how you would go about making 1200mL of 0.100 Molarity HNO3 from a concentrated solution that is 12 Molarity?
To make 1200mL of 0.100 M HNO3 (nitric acid) from a concentrated solution that is 12 M, you would need to perform a dilution. The process involves adding a calculated amount of the concentrated solution to a certain volume of solvent (usually water) to achieve the desired molarity.
Here are the steps to make the desired solution:
1. Calculate the volume of the concentrated solution required using the equation:
M1V1 = M2V2
M1 is the molarity of the concentrated solution (12 M)
V1 is the volume of the concentrated solution required (unknown)
M2 is the desired molarity (0.100 M)
V2 is the desired final volume (1200 mL or 1.2 L)
Plugging in these values gives:
(12 M) × V1 = (0.100 M) × (1.2 L)
2. Rearrange the equation and solve for V1:
V1 = (0.100 M) × (1.2 L) / (12 M)
= 0.010 L or 10 mL
Therefore, you would need to measure 10 mL of the concentrated 12 M HNO3 solution.
3. Now, prepare a volumetric flask or container by adding distilled water to a total volume of 1200 mL or 1.2 L.
4. Carefully measure out the 10 mL of the concentrated HNO3 solution using a graduated cylinder or pipette. Add it to the volumetric flask or container containing the water.
5. Mix the solution thoroughly by swirling or gently inverting the flask several times.
6. The resulting solution will have a concentration of approximately 0.100 M HNO3 and a total volume of 1200 mL.
Remember to handle concentrated acids with caution, following appropriate safety procedures, such as wearing protective gloves, goggles, and a lab coat.