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math

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(w+9)^3+56=0 write were w i a real number write answer in simplified radical form

write b^2/3 as a radical expression

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    for the second one you have b^2 under a radical sign with an index of 3 (or root of 3)

    You have some typos in the first one.. but if I am a reading it correctly.

    (w+9)^3 = -56

    take the cube root of both sides
    w + 9 = cube root of (-56)

    subtract 9.. the 9 will not be under the root.

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