Before a collision, the x-momentum of an object is 8.0 × 103 kilogram meters/second, and its y-momentum is 1.2 × 104 kilogram meters/second. What is the magnitude of its total momentum after the collision?
A. 1.4 × 104 kilogram meters/second
B. 2.0 × 104 kilogram meters/second
C. 3.2 × 104 kilogram meters/second
D. 5.7 × 104 kilogram meters/second
It depends upon what it collides with, and what type of collision it is. The momentum of "the object" will be changed.
All you can say is what the magnitude of the total momentum before the collision. It is about 1.44*10^4 kg m/s
I am amazed that people or schools are being paid to ask nonsensical questions like this.
To find the magnitude of the total momentum after the collision, you need to use the Pythagorean theorem.
The Pythagorean theorem states that the square of the hypotenuse (in this case, the magnitude of the total momentum) is equal to the sum of the squares of the other two sides (in this case, the x-momentum and y-momentum).
The formula for finding the magnitude of momentum is:
Magnitude of momentum = √(x-momentum^2 + y-momentum^2)
Let's plug in the given values:
Magnitude of momentum = √((8.0 × 10^3)^2 + (1.2 × 10^4)^2)
Now, calculate:
Magnitude of momentum = √(64.0 × 10^6 + 144.0 × 10^6)
Magnitude of momentum = √(208.0 × 10^6)
Magnitude of momentum = √(2.08 × 10^8)
Magnitude of momentum ≈ 1.44 × 10^4 kilogram meters/second
Rounding to the correct number of significant figures, the magnitude of the total momentum after the collision is approximately 1.4 × 10^4 kilogram meters/second.
Therefore, the correct answer is A. 1.4 × 10^4 kilogram meters/second.
To find the magnitude of the total momentum after the collision, we need to use the Pythagorean theorem.
The x-momentum before the collision is 8.0 × 10^3 kilogram meters/second.
The y-momentum before the collision is 1.2 × 10^4 kilogram meters/second.
Using the Pythagorean theorem, we can calculate the magnitude of the total momentum after the collision:
Magnitude of momentum = √(x-momentum^2 + y-momentum^2)
= √((8.0 × 10^3)^2 + (1.2 × 10^4)^2)
= √(64.0 × 10^6 + 144.0 × 10^6)
= √(208.0 × 10^6)
= √(2.08 × 10^8)
= 2.0 × 10^4 kilogram meters/second
Therefore, the magnitude of the total momentum after the collision is 2.0 × 10^4 kilogram meters/second.
The correct option is B. 2.0 × 10^4 kilogram meters/second.