math
posted by Robin .
x^24x+32=0.
would the final answer be 2 +or 2 sqrt7 ?

x^24x+32=0
a =1
b= 4
c= 32
4 +or sq root (4)^2 4(1)(32)
4 +or sq root 16128
4 +or sq root 112
you can't take the sq root of a () number so you can't solve this :/
How did you get 2 +or 2 sqrt7.
Perhaps I went wrong somewhere. 
hmmm. what's b^24ac? 16128 = 112
So, x = 2 ± 2√(7) = 2 ± 2√7 i
gotta watch those pesky minus signs 
the original question was
x^24x=32
can you help me solve? 
as I suspected, that makes it x^24x32=0
since 32=8*4,
(x8)(x+4) is the factorization