The diameter of a road roller is 140cm and its length is 2.2m. It takes 400 complete revolutions to move over to level a stretch of a road 2.2m wide find the surface area of stretch of road leveled in m sq.

To find the surface area of the stretch of road leveled, we need to calculate the area covered by each revolution of the road roller and then multiply it by the total number of revolutions.

First, let's find the circumference of the roller:
Circumference = π * diameter

Given that the diameter is 140 cm, we can calculate the circumference as follows:
Circumference = π * 140 cm

Now, let's convert the circumference from cm to meters by dividing it by 100:
Circumference = π * 140 cm / 100 = π * 1.4 m

Next, we need to find the distance covered in one revolution, which is equal to the circumference of the roller:
Distance covered in one revolution = Circumference = π * 1.4 m

Since it takes 400 complete revolutions to move over a stretch of road that is 2.2 m wide, we can calculate the total distance covered by the roller as:
Total distance covered = Distance covered in one revolution * Number of revolutions
Total distance covered = (π * 1.4 m) * 400

Finally, to find the surface area of the stretch of road leveled, we multiply the total distance covered by the width of the road:
Surface area = Total distance covered * Width of the road = (π * 1.4 m * 400) * 2.2 m

Calculating this expression gives us the surface area of the stretch of road leveled in square meters.

that's why I showed the circumference as pi*d, and not 2pi * r

Still, thanks for checking my work.

I dont know how can we solve this question please help me and give me the answer of this question

diameter is 140cm

it 's not radius sir

area = (400)(pi)(1.4m)(2.2m) = 3870 m^2