Minh is covering a necklace box with gift wrap. The necklace box is
15 centimeters long, 8 centimeters wide, and 2 centimeters high. What is
the minimum surface area of the paper that will cover the necklace box?
Its 332
322
What is the surface area of the box?
2(8*15) + 2(8*2) + 2(2*15) = ?
To calculate the minimum surface area of the paper needed to cover the necklace box, we need to consider all the individual sides of the box that need to be covered.
The necklace box has 6 sides: a top, a bottom, a front, a back, and two sides. We need to calculate the surface area of each side and then sum them up to find the total surface area.
The formula for calculating the surface area of a rectangular prism (such as the necklace box) is:
Surface Area = 2 * (length * width + width * height + height * length)
Given that the length of the box is 15 centimeters, the width is 8 centimeters, and the height is 2 centimeters, we can substitute these values into the formula:
Surface Area = 2 * (15 * 8 + 8 * 2 + 2 * 15)
Calculating this equation, we get:
Surface Area = 2 * (120 + 16 + 30)
Surface Area = 2 * 166
Surface Area = 332 square centimeters
Therefore, the minimum surface area of the paper needed to cover the necklace box is 332 square centimeters.