Physics
posted by Michael .
A car is driven east for a distance of 46 km, then north for 29 km, and then in a direction 29° east of north for 22 km. Determine (a) the magnitude (in km) of the car's total displacement from its starting point and (b) the angle (from east) of the car's total displacement measured from its starting direction.

X = 22*cos61 + 46 = 56.67 km.
Y = 22*sin61 + 29 = 48.24 km.
a. D^2 = X^2 + Y^2 = 5538.74
D = 74.4 km.
b. tanA = Y/X = 48.74/56.67 = 0.85124
A = 40.4o.
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