A wire that is 70 cm long, carrying a current of 6.5 A, is at right angles to a uniform magnetic field. The magnitude of the force acting on the wire is 0.60 N. What is the strength of the magnetic field?
To find the strength of the magnetic field, we can use the formula for the magnetic force on a current-carrying wire:
F = BIL
Where:
F is the force acting on the wire,
B is the strength of the magnetic field,
I is the current flowing through the wire,
L is the length of the wire.
In this case, we know that the force is 0.60 N, the current is 6.5 A, and the length of the wire is 70 cm (which we'll need to convert to meters).
First, let's convert the length of the wire to meters:
70 cm is equal to 0.70 m.
Now we can rearrange the formula to solve for B:
B = F / (IL)
Plugging in the values we have:
B = 0.60 N / (6.5 A * 0.70 m)
B = 0.60 N / 4.55 A*m
B ≈ 0.132 N/(A*m)
Therefore, the strength of the magnetic field is approximately 0.132 N/(A*m).