Statistics
posted by Clifford .
A private opinion poll is conducted for a politician favors decriminalizing marijuana possession. How large a sample is needed in order to be 95% confident that the sample proportion will not differ from the true proportion by more than 2%.

Formula to find sample size:
n = [(zvalue)^2 * p * q]/E^2
... where n = sample size, zvalue is found using a ztable for 95% confidence, p = .5 (when no value is stated in the problem), q = 1  p, ^2 means squared, * means to multiply, and E = .02.
Plug values into the formula and calculate n.
I hope this will help get you started.