Chemistry

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1.55 g of penatanol
250ml water
Heat from 10 to 38 degrees
Find hear of combustion

  • Chemistry -

    2C5H11OH + 15O2 ==> 10CO2 + 12H2O
    mols pentanol = grams/molar mass
    q = mass H2O x specific heat H2O x delta T.

    mol pentanol = 1.55g/88.15 = about 0.018 mol but you do it more accurately.

    dH comb = (q/0.018)*2 = about 3330 kJ or so/mol.

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