I don't understand how to do this problem because i don't see a precipitate. If you could show your work on the problem that would be great so i can follow along!
Identify the spectator ion(s) in the reaction
Zn(OH)2+ H2SO4→ZnSO4+ 2H2O
in aqueous solution.
1.There are no spectator ions.
2.Zn2+, (SO4)−2
3.Zn2+, OH−, H+, SO2−4
4.SO2−4
5.Zn2+
A spectator ion is an ion that appears the same on both sides of the equation.
Do you see any ions on either side of the equation?
To identify the spectator ion(s) in the reaction, we need to first understand the concept of spectator ions.
Spectator ions are ions that do not participate in the chemical reaction and remain unchanged throughout the reaction. They appear on both the reactant and product sides of the equation. In other words, spectator ions are present in solution but do not undergo any chemical changes.
To determine the spectator ion(s), we analyze the reaction and identify which ions remain the same on both sides of the equation.
Let's break down the reaction:
Zn(OH)2 + H2SO4 → ZnSO4 + 2 H2O
From the reaction, we can see that the ions involved are Zn2+, OH−, H+, and SO2−4.
Now, let's examine each ion:
Zn2+: This ion appears on both sides of the equation. Initially, it is combined with OH− to form Zn(OH)2, and in the product side, it is part of ZnSO4. Therefore, Zn2+ is not a spectator ion.
OH−: This ion appears on both sides of the equation as well. In the reactant side, it is part of Zn(OH)2, and in the product side, it forms H2O. Therefore, OH− is also not a spectator ion.
H+: This ion appears only on the reactant side of the equation and does not appear in any of the products. It undergoes a reaction with H2SO4 to form H2O. Therefore, H+ is not a spectator ion.
SO2−4: This ion appears on both sides of the equation. Initially, it is combined with H+ to form H2SO4, and in the product side, it remains unchanged as part of ZnSO4. Therefore, SO2−4 is a spectator ion.
Based on the analysis, the spectator ion(s) in the reaction Zn(OH)2 + H2SO4 → ZnSO4 + 2 H2O are SO2−4.
Therefore, the correct answer is option 4: SO2−4.