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A 71.1 kg man steps out a window and falls (from rest) 1.24 m to a sidewalk. What is his speed just before his feet strike the pavement?

  • physics -

    (1/2) m v^2 = m g h
    m cancels of course (Galileo)

    v = sqrt (2 g h)
    remember that

    v = sqrt (2*9.81*1.24)
    v = 4.93 m/s

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