Derive
posted by Mary .
Find the derivative of sin(2x + 3y)= 3xy + 5y2.
I have this so far
1) cos(2x+3y) * d/dx (2x+3y)= 3xy' + 3y + 5y'
2) cos (2x+3y) * [2 + 3y']= 3xy' + 3y + 5y'
3) 3y' cos (2x+3y) + 2cos(2x+3y)= 3xy' + 3y + 5y'
4) 3xy' + 5y'  (3y(cos(3x+3y)= 2 cos (2x + 3y)  3y
If I am wrong, can you please explain to me what I am doing wrong. Thank you
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