A flight attendant pulls her 70 N flight bag a distance of 253 m along a level airport floor at a constant speed. The force she exerts is 40 N at an angle of 53° above the horizontal

A) Find the work that she does on the flight bag
B) Find the work done by the force of friction on the bag

A) 40 cos53*253 = 6090 J

B) All of her work is done against friction. Friction does -6090 J

A) Well, the work done by the flight attendant on the flight bag can be calculated using the formula:

Work = Force x Distance x Cos(theta)

Where:
Force = 40 N (the force exerted by the flight attendant)
Distance = 253 m (the distance traveled by the flight bag)
Cos(theta) = Cos(53°) (since the angle is given as 53° above the horizontal)

Calculating the values:
Work = 40 N x 253 m x Cos(53°)

B) Now, let's move on to the work done by the force of friction on the bag. Since the flight bag is being pulled at a constant speed along a level floor, there is no change in kinetic energy, which means the work done by friction is zero.

So, the work done by the force of friction on the bag is zero.

Remember, it's always good to have a frictionless flight!

To find the work done in each case, we can use the formula:

Work = Force x Distance x cosθ

where:
- Work is the work done
- Force is the applied force
- Distance is the distance traveled
- θ is the angle between the applied force and the direction of motion

a) Find the work that she does on the flight bag:

Given:
- Force applied by the flight attendant (Fa) = 40 N
- Distance traveled (d) = 253 m
- Angle (θ) = 53°

Using the formula, we have:

Work = Force x Distance x cosθ
= 40 N x 253 m x cos(53°)

Using a calculator, we can find the value of cos(53°) ≈ 0.6. Plugging this value into the equation, we get:

Work = 40 N x 253 m x 0.6
≈ 6,072 J

Therefore, the work done by the flight attendant on the flight bag is approximately 6,072 Joules.

b) Find the work done by the force of friction on the bag:

The work done by the force of friction can be found by subtracting the work done by the applied force from the total work done. Since the applied force and the force of friction are in opposite directions, the work done by the force of friction will be negative.

Total work done = Work by applied force + Work by friction

Since we have already calculated the work done by the applied force as 6,072 J, we can now find the work done by friction.

Therefore,

Work by friction = Total work done - Work by applied force
= 0 - 6,072 J
= -6,072 J

Therefore, the work done by the force of friction on the bag is -6,072 Joules.

To find the work done by the flight attendant on the flight bag, we can use the formula:

Work = Force x Distance x cos(θ)

Where:
- Force is the component of the force in the direction of motion (in this case, 40 N)
- Distance is the distance the bag is pulled (253 m)
- θ is the angle between the direction of force and the direction of motion (53°)

A) Work done by the flight attendant on the flight bag:

Work = 40 N x 253 m x cos(53°)
Work = 40 N x 253 m x 0.6018
Work = 6055.2 J

Therefore, the flight attendant does 6055.2 Joules of work on the flight bag.

Now, to find the work done by the force of friction on the bag:

B) Work done by the force of friction on the bag:

Since the flight attendant is moving the bag at a constant speed, the work done by the force of friction is equal in magnitude and opposite in direction to the work done by the flight attendant.

So, the work done by the force of friction on the bag is -6055.2 J.

Note: The negative sign indicates that the force of friction is doing negative work, which means the friction is acting in the opposite direction of motion and taking energy away from the bag.