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Calculus

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Find relative maxima and minima of
g(x)= 2x^2+ 4000/x +10

  • Calculus -

    g ' (x) = 4x - 4000/x^2 + 0
    = 0 for a max/min

    4x = 4000/x^2
    4x^3 = 4000
    x^3 = 1000
    x = 10

    when x = 10
    f(10) = 200 + 400 + 10 = 610

    there is a relative min 610 at x=10

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