A man is currently 4 times as old as his son. In 4 yrs from now hell be 3 times as old as his son will be then. How old is his son now??
father=32
son=8
Thanks alot :) that helpe me alot
Can you get this started based on the help you got a little while ago?
Let m = man
Let s = son
Currently: give me the equation
four years from now: give me the equation.
Okay : Currently man is : 4s
Son : s
4 yrs froom now:
Man
3(s-3)
Son: s-3
You are correct with the m = 4s
for years from now the man will be m+4
and the son will be s +4
Now, what is their age relationship.
The man will be 3 times older than his son.
m + 4 = 3(s+4)
use that equation and m = 4s
to find their ages.
You have to read carefully and look for key words. For example, 3 times means to multiply by 3.
Four years from now means you have to add 4 years to their age.
If it said 4 years ago then you would subtract.
To solve this problem, let's assign variables for the ages of the man and his son. Let's say the son's age is S and the man's age is M.
According to the problem, the man is currently 4 times as old as his son, so we can write the equation: M = 4S
In four years from now, the man will be 3 times as old as his son will be then, so we can write the equation: M + 4 = 3(S + 4)
Let's use these equations to find the age of the son:
Substitute the value of M from the first equation into the second equation:
4S + 4 = 3(S + 4)
Distribute the 3 to S and 4:
4S + 4 = 3S + 12
Subtract 3S from both sides of the equation:
4S - 3S + 4 = 12
Simplify:
S + 4 = 12
Subtract 4 from both sides of the equation:
S = 12 - 4
Simplify:
S = 8
So, the son is currently 8 years old.