the sum of twelve ans a number is no greater than the sum of twice the number and -8
x+12 <= 2x + (-8)
now go for it
X+12<=2x+(-8)
To solve this problem, let's break it down into steps:
Step 1: Assign a variable to the unknown number.
Let's say the unknown number is x.
Step 2: Formulate the equation based on the given information.
The sum of twelve and a number is no greater than the sum of twice the number and -8. Mathematically, it can be expressed as:
12 + x ≤ 2x - 8
Step 3: Solve the equation for x.
To solve for x, we need to isolate it on one side of the equation. Let's do that:
12 + x ≤ 2x - 8
Subtract x from both sides:
12 ≤ x - 8
Add 8 to both sides:
20 ≤ x
So, the final answer is x ≥ 20.
This means any number greater than or equal to 20 will satisfy the given conditions.
Wow ... 10 posts in under 14 minutes! You must be taking a test or something.
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