Complete and balance each of the following equations for gas-evolution reactions. Identify all of the phases in your answer. HCl(aq)+K2SO3(aq)-->

2HCl(aq)+K2SO3(aq)➡️2KCl(aq)+SO2(g)+H2O(l)

Is is a gas evolution reaction:)

To balance the equation for the gas-evolution reaction between HCl(aq) and K2SO3(aq), we need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's the step-by-step process to balance the equation:

Step 1: Write down the unbalanced equation:
HCl(aq) + K2SO3(aq) -> ___ + ___

Step 2: Identify the elements that are involved in the reaction. In this case, we have hydrogen (H), chlorine (Cl), potassium (K), sulfur (S), and oxygen (O).

Step 3: Balance the elements that appear in only one compound first. In this case, we start with sulfur (S):
K2SO3(aq) contains one sulfur atom, so we need one sulfur atom on the product side. Therefore, we write K2SO3(aq) -> SO2(g).

Step 4: Now let's balance the oxygen (O) atoms:
K2SO3(aq) contains three oxygen atoms, so we need three oxygen atoms on the product side. Therefore, we add another SO2:
K2SO3(aq) -> SO2(g) + SO2(g)

Step 5: Balance the elements that appear in multiple compounds. In this case, we balance the hydrogen (H) and chlorine (Cl) atoms:
HCl(aq) contains one hydrogen atom and one chlorine atom. The product side currently has no hydrogen or chlorine, so we need to add two molecules of HCl:
HCl(aq) + K2SO3(aq) -> SO2(g) + SO2(g) + 2HCl(g)

Step 6: Finally, balance the potassium (K) atoms:
K2SO3(aq) contains two potassium atoms, so we need two potassium atoms on the product side. We add two molecules of KCl:
HCl(aq) + K2SO3(aq) -> SO2(g) + SO2(g) + 2HCl(g) + 2KCl(aq)

The balanced equation for the gas-evolution reaction between HCl(aq) and K2SO3(aq) is:
2HCl(aq) + K2SO3(aq) -> SO2(g) + SO2(g) + 2HCl(g) + 2KCl(aq)

Please note that the phases have been included in the final balanced equation:
2HCl(aq) + K2SO3(aq) -> SO2(g) + SO2(g) + 2HCl(g) + 2KCl(aq)

To complete and balance the equation for the gas-evolution reaction between HCl and K2SO3, we need to determine the products formed and balance the number of atoms on both sides of the equation.

First, let's identify the products formed when HCl and K2SO3 react. From the given reactants, we can see that HCl contains hydrogen chloride (HCl) in an aqueous solution, and K2SO3 contains potassium sulfite (K2SO3) in an aqueous solution.

The gas-evolution reaction between HCl and K2SO3 typically produces a gas called sulfur dioxide (SO2). Additionally, the remaining ions from the reactants will combine to form a salt and water.

Therefore, the balanced equation for the reaction is:

2HCl(aq) + K2SO3(aq) → SO2(g) + 2KCl(aq) + H2O(l)

In this balanced equation, the coefficients in front of each compound indicate the number of molecules or moles involved in the reaction. The phases of the substances are denoted as (aq) for aqueous solutions, (g) for gases, and (l) for liquid water.

So, the complete and balanced equation for the gas-evolution reaction between HCl and K2SO3 is:

2HCl(aq) + K2SO3(aq) → SO2(g) + 2KCl(aq) + H2O(l)

2HCl(aq) + K2SO3(aq) ==> H2SO3(aq) + 2KCl(aq)

(Note: some may argue that H2SO3 will give SO2(g) + H2O(l) but that isn't clear from the concentrations(or lack thereof) in the problem.).