The speed of all electromagnetic waves in
empty space is 3.00 × 108 m/s. What is the wavelength of visible light emitted at 7.2 × 108 MHz?
Answer in units of m
frequency f = 7.2 × 10^8 MHz
= 7.2*10^14 Hz
Wavelength (m) = (speed of light, m/s)/(frequency, Hz)
= 3.00*10^8/7.2*10^14 = 4.17*10^-7 m
= 417 nm
That correspnds to violet light
The formula to calculate the wavelength of a wave is given by:
wavelength = speed of light / frequency
Where:
- Speed of light = 3.00 × 10^8 m/s (given)
- Frequency = 7.2 × 10^8 MHz
First, we need to convert the frequency from megahertz (MHz) to hertz (Hz). Since 1 MHz = 10^6 Hz, we can convert the frequency as follows:
Frequency (Hz) = 7.2 × 10^8 MHz * 10^6 Hz/1 MHz = 7.2 × 10^14 Hz
Now we can substitute the values into the formula to calculate the wavelength:
wavelength = speed of light / frequency
wavelength = (3.00 × 10^8 m/s) / (7.2 × 10^14 Hz)
Calculating the value:
wavelength = 4.17 × 10^-7 meters
Therefore, the wavelength of the visible light emitted at 7.2 × 10^8 MHz is approximately 4.17 × 10^-7 meters.
To find the wavelength of visible light emitted at a frequency of 7.2 × 10^8 MHz, we can use the formula:
Wavelength = Speed of Light / Frequency
Here's how we can calculate it:
1. Convert the frequency from megahertz (MHz) to hertz (Hz):
7.2 × 10^8 MHz = 7.2 × 10^8 × 10^6 Hz = 7.2 × 10^14 Hz
2. Now, we can substitute the values into the formula:
Wavelength = (3.00 × 10^8 m/s) / (7.2 × 10^14 Hz)
3. Perform the division:
Wavelength ≈ 4.17 × 10^-7 m
So, the wavelength of the visible light emitted at a frequency of 7.2 × 10^8 MHz is approximately 4.17 × 10^-7 meters (m).