Algebra

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Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 236 miles in the same time that Dana travels 224 miles. If Chuck’s rate of travel is 3 mph more than Dana’s, and they travel the same length of time, at what speed does Chuck travel?

  • Algebra -

    r mi/h = Dana's rate.
    r * t = 224 miles.
    t = 224/r.

    3)224r+3) mi/h = Chuck's rate.
    (r+3)t = 236
    Replace t with 224/r:
    (r+3)224/r = 236
    Multiply both sides by r:
    (r+3)224 = 236r
    224r + 672 = 236r
    236r - 224r = 672
    12r = 672
    r = 56 mi/h = Dana's speed.
    r+3 = 59 mi/h = Chuck's speed.

  • Algebra -

    Correction: Chuck's rate = (r+3)mi/h.

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