math
posted by mace .
solve the compound inequalities as demostrated being careful of how a negative x term is handled in the solving process show all math work arriving at the solutions display a simple line qraph for each solution set as demostrated. 1<3+2x<11 (Your and compound inequality) 1x>3 or 5x1>19 (your or Copmound inequality)

1<3+2x<11
subtract 3
4 < 2x < 8
divide by 2
2 < x < 4
1x ≥ 3 OR 5x1 > 19
x ≥ 4 OR 5x > 20
x ≤ 4 OR x > 4
which obviously includes every value of x
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