posted by zachary .
given the following polynomial find the zero and multiply of each
were the graph touches the x axis
number of turning points
0 = (x-4)(x+5)(x-5)
Set each equal to zero and solve for x. That will give you three different zeros. Each occurs only once.
f(x) = (x-4)(x-5)(x+5)
3 roots, each of multiplicity 1
The graph crosses the axis at each root, so it has to turn around 2 times.