a 2500 car enters curve with a radius of 45 m .if the car is moving at speed of 35 m/s.what is the centripetal force that maintains the car s circular motion the curve ?
To determine the centripetal force that maintains the car's circular motion in the curve, we can use the centripetal force formula:
Fc = (m * v^2) / r
Where:
Fc is the centripetal force
m is the mass of the car
v is the velocity of the car
r is the radius of the curve
Since we are not given the mass of the car, we will assume a standard value for average cars, which is around 1500 kg.
Plugging in the values:
m = 1500 kg
v = 35 m/s
r = 45 m
Fc = (1500 kg * (35 m/s)^2) / 45 m
Now let's calculate it step by step:
Step 1: Calculate the velocity squared (v^2)
v^2 = 35 m/s * 35 m/s = 1225 m^2/s^2
Step 2: Calculate the numerator of the equation (m * v^2)
Numerator = 1500 kg * 1225 m^2/s^2 = 1,837,500 kg m^2/s^2
Step 3: Calculate the centripetal force (Fc) by dividing the numerator by the radius (r)
Fc = 1,837,500 kg m^2/s^2 / 45 m
Finally, we can simplify the expression:
Fc ≈ 40,833.33 N
Therefore, the centripetal force that maintains the car's circular motion in the curve is approximately 40,833.33 Newtons.