Calculate [OH- ] and pH for each of the following strong base solutions. (Kw = 1.0 10-14.)
3.155 g of KOH in 460.0 mL of solution]
how do you do this
M = mols/L
You get mols from grams/molar mass.
You get L from 460 mL and convert to L.
(OH^-) = M
pOH = -log(OH^-)
pH + pOH = pKw = 14. You know pOH and pKw, solve for pH.