A flagpole and a building stands on the same horizontal level.From the point P at the bottom of the building.the angle of elevation of the top T of the flagpole is 65 degrees from the top Q of the building the angle of elevation of the point T is 25 degrees.If the building is 20m high,Calculate
(a)Distance PT
(b)Height of the flagpole
(c)Distance QT.
canyou explain with a diagram and explain better
∆PQT=65-25=40°. ∆PST=90+65=115.
PT=? ST=20m
PTsin40°=20sin115°
PT=28.2m
i dont understand break it down that i can understand.
Height of the flagpole
Sin65°=X/28.2
X=28.2sin65°=25.6m
Distance QT
Cos65°=25.6/X
X=25.6/cos65°=11.9m
To find distance QT
Cos25°=11.9/X
X=11.9/cos25°=13.1m