A flagpole and a building stands on the same horizontal level.From the point P at the bottom of the building.the angle of elevation of the top T of the flagpole is 65 degrees from the top Q of the building the angle of elevation of the point T is 25 degrees.If the building is 20m high,Calculate

(a)Distance PT
(b)Height of the flagpole
(c)Distance QT.

canyou explain with a diagram and explain better

∆PQT=65-25=40°. ∆PST=90+65=115.

PT=? ST=20m
PTsin40°=20sin115°
PT=28.2m

i dont understand break it down that i can understand.

Height of the flagpole

Sin65°=X/28.2
X=28.2sin65°=25.6m

Distance QT

Cos65°=25.6/X
X=25.6/cos65°=11.9m
To find distance QT
Cos25°=11.9/X
X=11.9/cos25°=13.1m

I don't understand at all is like u don't no what u are doing

Pls I don't understand ,pls explain with diagram

Correct

Plese explain better by using normal arithmetic signs

for distance QT its not cos 65, you wouldn't get 11.9 with that, it is Tan 65, then u would get 11.9