What volume (mL) of a 3.23 %w/v saline solution contains 69.1 mg of NaCl?
(0.0691 g of NaCl/ x mL)*100=3.23% w.v saline solution
Solve for x
0.0691 g of NaCl/0.0323= volume in mL
To find the volume of a solution, we need to use the equation:
Volume = Mass / Concentration
Given:
Mass of NaCl = 69.1 mg
Concentration of saline solution = 3.23 %w/v
First, we need to convert the mass of NaCl from milligrams (mg) to grams (g) for consistency. There are 1000 milligrams in a gram, so
Mass of NaCl = 69.1 mg / 1000 = 0.0691 g
Next, we need to convert the concentration from a percentage to a decimal fraction. The percentage concentration refers to the mass of solute (NaCl) in grams per 100 mL of solution. So, for a 3.23% concentration, we have:
Concentration = 3.23 / 100 = 0.0323 g/mL
Now we can use the equation:
Volume = Mass / Concentration
Volume = 0.0691 g / 0.0323 g/mL = 2.14 mL
Therefore, the volume of a 3.23% w/v saline solution containing 69.1 mg of NaCl is 2.14 mL.