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A 12 g sample of Ne is added to a container that also holds .78 mol of helium gas. What is the partial pressure of helium if the total pressure, after mixing is 2.43 atm?

  • chemistry -

    mol He = 0.78
    mols Ne = grams/molarmass
    total mols = nHe + nNe.

    pHe = XHe*Ptotal
    pNe = XNe*Ptotal
    Ptotal = 2.43 atm.

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