Acid rain has a pH value of 3.0, whereas

normal rain has a pH value of 5.6. Calculate
the ratio of the hydronium ion in acid rain to
that in normal rain.

To calculate the ratio of the hydronium ion ([H3O+]) in acid rain to that in normal rain, we can use the pH values.

The pH is calculated using the formula: pH = -log[H3O+]

For acid rain:
pH = 3.0

So, 3.0 = -log[H3O+]

For normal rain:
pH = 5.6

So, 5.6 = -log[H3O+]

To find the ratio, we need to compare the concentrations of [H3O+] in both cases. The concentration of [H3O+] is inversely proportional to the pH value.

Using the formula, we find:

[H3O+] in acid rain = 10^(-pH)
[H3O+] in normal rain = 10^(-pH)

Substituting the pH values:

[H3O+] in acid rain = 10^(-3.0)
[H3O+] in normal rain = 10^(-5.6)

Now, to find the ratio:

Ratio = [H3O+] in acid rain / [H3O+] in normal rain
= (10^(-3.0)) / (10^(-5.6))

To simplify, we can divide the two powers of 10:

Ratio = 10^(5.6 - 3.0)

Using logarithmic properties, we get:

Ratio = 10^(2.6)

Finally, we can calculate the ratio:

Ratio ≈ 398.107

Therefore, the ratio of the hydronium ion in acid rain to that in normal rain is approximately 398.107.

To calculate the ratio of the hydronium ion in acid rain to that in normal rain, we can use the equation for pH:

pH = -log[H3O+]

Given that acid rain has a pH value of 3.0, we can calculate the hydronium ion concentration ([H3O+]) in acid rain using the equation:

[H3O+] = 10^(-pH)

Substituting the pH value of 3.0 into the equation:

[H3O+] = 10^(-3.0)

Calculating this using a calculator:

[H3O+] = 0.001

Similarly, for normal rain with a pH value of 5.6, the hydronium ion concentration can be calculated using the equation:

[H3O+] = 10^(-pH)

Substituting the pH value of 5.6 into the equation:

[H3O+] = 10^(-5.6)

Calculating this using a calculator:

[H3O+] = 0.000025

Now, to find the ratio of the hydronium ion in acid rain to that in normal rain, we can divide the hydronium ion concentration in acid rain by the hydronium ion concentration in normal rain:

Ratio = [H3O+] (acid rain) / [H3O+] (normal rain)

Ratio = 0.001 / 0.000025

Calculating this using a calculator:

Ratio = 40

Therefore, the ratio of the hydronium ion in acid rain to that in normal rain is 40.

pH 3.0 has (H3O^+) = 1E-3

pH 5.6 has (H3O^+)= 2.51E-6
ratio = 1E-3/2.51E-5 = ?

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