In a basket of 24 mangoes 1/3 were yellow 5/8 were green and the rest were orange.

1. what fraction of the mangoes were green and ripe?
2. How mangoes green?
3. How many mangoes were orange?
4. What fraction of the mangoes were orange?

yellow mangoes = (1/3)(24) = 8

green mangoes = (5/8)(24) = 15
which leaves 1 mango as orange.

or 1/3 + 5/8 = 23/24
leaving 1/24 for the orange mangoes
and (1/24)(24) = 1

Anissa

To answer these questions, we need to use the given information and do some calculations. Let's go step by step:

1. To find the fraction of mangoes that were green and ripe, we need to multiply the fractions representing the percentage of mangoes that were green (5/8) and the percentage of ripe mangoes within the green ones (we assume all green mangoes were ripe). To do this, we need to multiply the two fractions: (5/8) * 1 = 5/8. So, 5/8 of the mangoes were green and ripe.

2. To find how many mangoes were green, we multiply the total number of mangoes (24) by the fraction that represents the percentage of green mangoes. So, (5/8) * 24 = 15. Hence, there were 15 green mangoes.

3. To find how many mangoes were orange, we first need to find the difference between the total number of mangoes (24) and the sum of the number of yellow (1/3) and green (5/8) mangoes. We can find the sum of the yellow and green mangoes by multiplying their fractions by 24 and adding the results: (1/3) * 24 + (5/8) * 24. Evaluating this expression, we get 8 + 15 = 23. Therefore, there were 24 - 23 = 1 orange mango.

4. To find the fraction of mangoes that were orange, we divide the number of orange mangoes (1) by the total number of mangoes (24). So, the fraction of mangoes that were orange is 1/24.

In summary:
1. The fraction of mangoes that were green and ripe: 5/8.
2. The number of green mangoes: 15.
3. The number of orange mangoes: 1.
4. The fraction of mangoes that were orange: 1/24.