Factor the expression. x2 + 6x + 48
a) (x + 1)(x + 48)
b) (x + 6)^2
c) (x + 6)(x + 8)
d) Prime Polynomial
e) Not factorable
i got e... am i doing something wrong
(X+1)(x+48). X^2+47x+48
I have to factor the expression listed x^2 + 6x +48
(X+6)^2. X^2+6x+32
@blue those where the choices they gave
Oh sorry dear let me check it again
I believe the correct answer is c.
@ms. sue that would give me x^2+14x+48 so I guess it would be D
does anyone else know??
x^2 + 6x + 48 does not factor using rational numbers
(can you think of two numbers which when multiplied will give you 48 and when added will give you 6 ? )
I would pick e)
To factor the expression x^2 + 6x + 48, you need to find two binomials that, when multiplied together, give you the original expression.
Here's how you can do it:
1. First, look for two numbers whose product is equal to the product of 48 and whose sum is equal to 6 (the coefficient of the middle term). In this case, the numbers are 4 and 12 since 4 * 12 = 48 and 4 + 12 = 16.
2. Now, split the middle term (6x) into the two numbers you found in the previous step. Rewrite the expression as: x^2 + 4x + 12x + 48.
3. Next, group the terms: (x^2 + 4x) + (12x + 48).
4. Factor out the common factors from each group: x(x + 4) + 12(x + 4).
5. Notice that you now have a common binomial factor of (x + 4). Factor that out: (x + 4)(x + 12).
As a result, the expression x^2 + 6x + 48 can be factored as (x + 4)(x + 12).
So, the correct answer in this case is option c) (x + 6)(x + 8). Option e) "Not factorable" would be incorrect because the given expression can indeed be factored.