Trigonometry
posted by AwesomeGuy .
Solve the equation for all values of x.
2sin(2x)√3=0, on the interval [0,2π).

sin2x = √3/2
so, 2x = π/3, 2π/3, 7π/3, 8π/3
x = π/6, π/3, 7π/6, 4π/3
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