How do I write an equation of a line that passes through the point (-28, -5) and is parallel to
y= -5 45
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8. 2
To write the equation of a line that is parallel to another line, we need to use the same slope as the given line. In this case, the given line is y = -5, which has a slope of 0 since it is a horizontal line.
Since the line we want to write an equation for is parallel to this line, it will also have a slope of 0. Now we can use the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
We are given the point (-28, -5) that the line passes through. Plugging this information into the equation, we have:
y - (-5) = 0(x - (-28))
Simplifying this equation, we get:
y + 5 = 0(x + 28)
Next, we can simplify further by multiplying through the 0 on the right side of the equation:
y + 5 = 0
Finally, we can subtract 5 from both sides of the equation to isolate y:
y = -5
Therefore, the equation of the line that passes through the point (-28, -5) and is parallel to y = -5 is y = -5.