# math

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the 2 consecutive multiples of 6 up to 116

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the general expression for consecutive multiples of 6 is 6N, 6(N + 1), 6(N +2), etc. find three consecutive multiples of 6 such that 4 times the first exceeds twice the third by 12. Let N be the first, so n+1 is next, etc. 4(6(n+1))-2(6(n+3))=12 …
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Hi i posted this question: the general expression for consecutive multiples of 6 is 6N, 6(N + 1), 6(N +2), etc. find three consecutive multiples of 6 such that 4 times the first exceeds twice the third by 12. and than Bobpursley replied: …
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