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f(x)=2x2−146x+c has 2 roots that are positive prime numbers. What is c?

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    you know the factors are

    (x-a)(2x-b)
    where 2a+b=146

    b must be even, so b=2k
    a+k = 73
    so, try
    a=71 k=2
    f(x) = (x-71)(2x-4) c=284

    For any other smaller value of a, k must be even, so the above is the only solution

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