heating copper sulfate pentahydrate will evaporate the water from the crystals. leaving anhydrous copper sulfate,. a white powder. what mass of anhydrous CuSO4 would be produced by heating 500.0g of CuSO4*5H2O
What's the percent CuSO4 in CuSO4.5H2O?
%CuSO4 x 500 g = g CuSO4.
To calculate the mass of anhydrous copper sulfate (CuSO4), we need to determine the percentage of CuSO4 in the hydrated form CuSO4*5H2O.
1. Determine the molar mass of CuSO4*5H2O:
- Cu: 63.55 g/mol
- S: 32.07 g/mol
- O: 16.00 g/mol
- H: 1.01 g/mol
- For the water component, 5H2O (5 * 18.02 g/mol = 90.10 g/mol)
Total molar mass: (63.55 + 32.07 + 4 * 16.00) + 90.10 = 249.69 g/mol
2. Calculate the molar mass of CuSO4:
- Cu: 63.55 g/mol
- S: 32.07 g/mol
- O: 16.00 g/mol
Total molar mass: 63.55 + 32.07 + 4 * 16.00 = 159.61 g/mol
3. Determine the mass of CuSO4 in the hydrated form:
The mass percent composition of CuSO4 in CuSO4*5H2O is 159.61 g/mol / 249.69 g/mol = 0.639.
Mass of CuSO4 = Mass of CuSO4*5H2O × mass percent composition of CuSO4
Mass of CuSO4 = 500.0 g × 0.639 = 319.5 g
Therefore, if you heat 500.0 g of CuSO4*5H2O, you would produce 319.5 g of anhydrous CuSO4.
To determine the mass of anhydrous copper sulfate (CuSO4) produced by heating 500.0g of CuSO4·5H2O, you need to account for the mass lost due to the evaporation of water.
First, you need to find the molar mass of CuSO4·5H2O and CuSO4. The molar mass of CuSO4·5H2O can be calculated by adding up the molar masses of its individual elements:
- Copper (Cu) has a molar mass of 63.55 g/mol
- Sulfur (S) has a molar mass of 32.07 g/mol
- Oxygen (O) has a molar mass of 16.00 g/mol
- Hydrogen (H) has a molar mass of 1.01 g/mol
The molar mass of CuSO4·5H2O would be:
(63.55g/mol) + (32.07g/mol) + (4 × 16.00g/mol) + (5 × (2 × 1.01g/mol)) = 249.69 g/mol
Next, you need to calculate the mass of water (H2O) in CuSO4·5H2O. Each molecule of CuSO4·5H2O contains 5 water molecules, so the mass of water is:
(5 × (2 × 1.01g/mol)) = 10.10 g
Now you can calculate the mass of anhydrous CuSO4 by subtracting the mass of water from the initial mass of CuSO4·5H2O:
500.0 g - 10.10 g = 489.90 g
Therefore, heating 500.0g of CuSO4·5H2O would produce approximately 489.90g of anhydrous CuSO4.