Find the maximum height reached by a ball thrown upward at a velocity of 95 ft/s
To find the maximum height reached by a ball thrown upward at a velocity of 95 ft/s, we can use the kinematic equation for vertical motion:
v² = u² + 2as
Where:
v is the final velocity (which would be 0 when the ball reaches its highest point)
u is the initial velocity (which is 95 ft/s in this case)
a is the acceleration due to gravity (-32 ft/s² in this case)
s is the displacement (maximum height reached, what we want to find)
Rearranging the equation, we have:
0² = 95² + 2(-32)s
0 = 9025 - 64s
64s = 9025
s = 9025/64
s ≈ 140.82 ft
Therefore, the maximum height reached by the ball is approximately 140.82 ft.