I divide exactly by 100 my first two digits are equal the sum of my four digits is 8

4,400

4 4 0 0

To find the number that satisfies the given conditions, we can go through the following steps:

Step 1: Consider the number in the general form of "abcd", where a, b, c, and d represent the digits of the number.

Step 2: Since the number divides exactly by 100, it means that the last two digits, c and d, should be zero. Hence, the number becomes "ab00".

Step 3: We know that the sum of the four digits is 8. So, a + b + 0 + 0 = 8. Simplifying this equation gives us a + b = 8.

Step 4: From the given condition that the first two digits are equal, we can write a = b.

Step 5: Substituting the value of a in terms of b into the equation derived in step 3, we get b + b = 8. Simplifying further, we get 2b = 8, so b = 4.

Step 6: Since a = b, we can conclude that a = 4 as well.

Step 7: Finally, the number that satisfies all the given conditions is 4400.

Therefore, the number that divides exactly by 100, with the first two digits equal and the sum of all four digits being 8, is 4400.

4400

four digits abcd

a+a+0+0=8
2a=8
a=4
answer 4400

Wow

How do you get that answer?

What do you do with the information in the question to get that?

"I divide exactly by 100. My first two digits are equal. The sum of my four digits is 8."

I'm at a complete loss, can anyone shed any light on it for me please?

Bb