Calculate the volume in liters of the gas (O2) at STP if it was massed at 6.75 x 105 grams.

To calculate the volume of the gas at STP (Standard Temperature and Pressure), we can use the Ideal Gas Law equation: PV = nRT. However, since we are given the mass of the gas, we'll first need to find the number of moles of gas using the molar mass of oxygen (O2), which is approximately 32 g/mol.

Here's the step-by-step process to find the volume in liters:

Step 1: Convert the given mass from grams (g) to moles (mol).

Mass of O2 = 6.75 x 10^5 grams
Molar mass of O2 = 32 g/mol

Number of moles (n) = Mass / Molar mass
n = 6.75 x 10^5 g / 32 g/mol

Step 2: Calculate the volume using the Ideal Gas Law equation.

The Ideal Gas Law equation is PV = nRT, where:
P = pressure (at STP, pressure = 1 atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (at STP, temperature = 273.15 K)

Rearrange the equation to solve for V:
V = (nRT) / P

Substituting the values:
P = 1 atm
n = calculated in step 1
R = 0.0821 L·atm/mol·K
T = 273.15 K

V = (nRT) / P
V = (6.75 x 10^5 mol) x (0.0821 L·atm/mol·K) x (273.15 K) / (1 atm)

Step 3: Calculate the final volume.

Now you can calculate the volume (V) in liters using the given values.

V = (6.75 x 10^5 mol) x (0.0821 L·atm/mol·K) x (273.15 K) / (1 atm)

By performing the calculation, you will get the volume of the gas in liters at STP.